👣 **Graphical representation of the solution of a linear inequalit y**

(a) To represent the solution of a linear inequality in one or two variables graphically in a plane, we proceed as follows:

(i) If the inequality involves ‘≥’ or ‘≤’, we draw the graph of the line as a **thick line** to indicate that the points on this line are included in the solution set.

(ii) If the inequality involves ‘>’ or ‘<’, we draw the graph of the line as **dotted line** to indicate that the points on the line are excluded from the solution set.

(b) Solution of a linear inequality in one variable can be represented on number line as well as in the plane but the solution of a linear inequality in two variables of the type *a x+by>c*,

*a*,

*x*+b*y*≥c*a* or

(c) Two or more inequalities taken together comprise a system of inequalities and the solutions of the system of inequalities are the solutions common to all the inequalities comprising the system.

*x*+b*y**a*(

*x*+by≤c*a*≠0,

*b*≠0) can be represented in the plane only.

(c) Two or more inequalities taken together comprise a system of inequalities and the solutions of the system of inequalities are the solutions common to all the inequalities comprising the system.

is illustrated on the graph below.

The coordinates of any point in the shaded area satisfy

✍ Solution:

The region has the line

The coordinates of 3 points on this line are (0, -7), (2, 1) and (3, 5).

These points are plotted and a2≥(4×3)-7 or 2≥5.

This statement is

Therefore the

✍ Solution:

The line

Now 3 points on the line can be calculated, for example (0, 5), (2, 4) and (4, 3).

Next, a point on one side of the line is selected, for example (2, 3), where

2+2×3<10 or 8<10.

This is clearly true and so points on this side of the line will satisfy the inequality. This side of the line can now be shaded, as below.

Solving a System of Inequalities after Sketching each Graph of each Linear Inequality

👣 **Graphical Approach to Inequalities**

When an inequality involves two variables, the inequality can be represented by a region on a graph. For example, the inequality

*x*+

*y*≥24

is illustrated on the graph below.

The coordinates of any point in the shaded area satisfy

*x*+*y*≥4.Note:

The coordinates of any point on the line satisfy *x*+*y*=4.

If the inequality had been *x*+*y*>4, then a __dashed__ line would have been used to show that points on the line do not satisfy the inequality, as below.

📌 Worked Example 1

Shade the region which satisfies the inequality

*y*≥4

*x*-7.

✍ Solution:

The region has the line

*y*=4*x*-7 as a boundary, so first of all the line*y*=4*x*-7 is drawn.The coordinates of 3 points on this line are (0, -7), (2, 1) and (3, 5).

These points are plotted and a

__solid__line is drawn through them.A solid line is drawn as the inequality contains a ‘≥’ sign which means that points on the boundary are included.

Next, select a point such as (3, 2). (It does not matter on which side of the line the point lies.)

If the Values, *x*=3 and *y*=2, are substituted into the inequality, we obtain

This statement is

__clearly false__and will also be false for any point on that side of the line.Therefore the

__other__side of the line should be shaded, as shown.📌 Worked Example 2

Shade the region which satisfies the inequality

*x*+2

*y*<10.

✍ Solution:

The line

*x*+2*y*=10 will form the boundary of the region, but will not itself be included in the region. To show this, the line should be drawn as a__dashed__line.Before drawing the line, it helps to rearrange the equation as

*y*=½(10-

*x*).

Now 3 points on the line can be calculated, for example (0, 5), (2, 4) and (4, 3).

This line is shown below.

Next, a point on one side of the line is selected, for example (2, 3), where

*x*=2 and*y*=3. Substituting these values for*x*and*y*into the inequality givesThis is clearly true and so points on this side of the line will satisfy the inequality. This side of the line can now be shaded, as below.

Solving a System of Inequalities after Sketching each Graph of each Linear Inequality

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